Question

Divide 36 into two parts in such way that ⅕ of one part is equal to ⅐ of the other
Illustrated by the following Statement
-11/13× -17/5 = 17/5 × -11/13

Answer 1

Let, one part of 36=x

Therefore, another part of 36=36-x

Now, we are given that 1/5 of one part is equal to 1/7 of the other.

A.T.S.

$\frac{1x}{5} = \frac{1}{7}(36 - x)$

$\frac{1x}{5} = \frac{36}{7} - \frac{x}{7}$

$\frac{1x}{5} + \frac{x}{7} = \frac{36}{7}$

$\frac{7x + 5x}{35} = \frac{36}{7}$

$\frac{12x}{35} = \frac{36}{7}$

$x = \frac{36}{7} \times \frac{35}{12}$

x=15

Therefore, the one part is 15 and another part is 36-15=21

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Answer 2

Answer:

$\huge\boxed{\fcolorbox{red}{pink}{Your's Answer}}$

$\red {QUESTION}$

Divide 36 into two parts in such way that ⅕ of one part is equal to ⅐ of the other Illustrated by the following Statement:

-11/13× -17/5 = 17/5 × -11/13

$\green {ANSWER}$

Let one part of 36= x

Hence, another part of 36= 36-x

We are given that ⅕ of one part is equal to ⅐ of the other.

According to statement:

$\frac{x}{5} = \frac{1}{7} (36 - x)$

$\frac{x}{5} = \frac{36}{7} - \frac{x}{7}$

$\frac{x}{5} + \frac{x}{7} = \frac{36}{7}$

$\frac{7x + 5x}{35} = \frac{36}{7}$

$\frac{12x}{35} = \frac{36}{7}$

$x = \frac{36}{7} \times \frac{35}{12}$

$x = 15$

Therefore, one part is 15

and other part is 36-15 = 21

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