Divide 39 in 3 parts in a.p. such that the largest exceeds the smallest by 6.
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Let the smallest term be a and the common difference be d.
Now,
(a+2d)-a=6
2d=6
d=3
Note that the sum has been given as 39.
We need to divide 39 into 3 parts in ap, we also have the common difference being 3, therefore,
a+a+d+a+2d=39
3a+3d=39
3a+9=39
3a=30
a=10
Hence the ap would be,
10, 13, 16
Now,
(a+2d)-a=6
2d=6
d=3
Note that the sum has been given as 39.
We need to divide 39 into 3 parts in ap, we also have the common difference being 3, therefore,
a+a+d+a+2d=39
3a+3d=39
3a+9=39
3a=30
a=10
Hence the ap would be,
10, 13, 16
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