Question

divide -39x^4 by root 13x^2

Answer 1

Hope this helps u dude

Answer 2

Answer:

$-3\sqrt{13}x^2$

Step-by-step explanation:

Given expression,

$\frac{-39x^4}{\sqrt{13}x^2}$

By using quotient rule of exponent,

$\frac{-39x^{4-2}}{\sqrt{13}}$

$\frac{-39x^2}{\sqrt{13}}$

Rationalize the denominator by multiply both numerator and denominator with √13 ,

$\frac{-39\sqrt{13}x^2}{13}$

$-3\sqrt{13}x^2$