Question

divide √3a^4+2a^3 - 6a by 3a​

Answer 1

Answer:

this is our answers two ways

Answer 2

The division of the given expression

$\frac{\sqrt{3}a^4+2a^3-6a}{3a}=\frac{a^{3}}{\sqrt{3}}+\frac{2a^2}{3}-2$

Step-by-step explanation:

Given that divide the expression $\sqrt{3}a^4+2a^3-6a$ by 3a

To find the division of the given expression :

$\frac{\sqrt{3}a^4+2a^3-6a}{3a}$

$=\frac{\sqrt{3}a^4}{3a}+\frac{2a^3}{3a}+\frac{-6a}{3a}$

$=\frac{\sqrt{3}a^4a^{-1}}{\sqrt{3}\times \sqrt{3}}+\frac{2a^3a^{-1}}{3}-2aa^{-1}$ ( using the property $\frac{1}{a^m}=a^{-m}$ )

$=\frac{a^{4-1}}{\sqrt{3}}+\frac{2a^{3-1}}{3}-2a^{1-1}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=\frac{a^{3}}{\sqrt{3}}+\frac{2a^{2}}{3}-2a^{0}$  ( by $x^0=1$ )

$=\frac{a^{3}}{\sqrt{3}}+\frac{2a^2}{3}-2$

Therefore $\frac{\sqrt{3}a^4+2a^3-6a}{3a}=\frac{a^{3}}{\sqrt{3}}+\frac{2a^2}{3}-2$