Question

divide 40 in two parts such that 1/4 of part is 3/8 of other part​

Answer 1

Answer:

Let the 1st part be x

2nd part be 40-x

A/Q. (1/4)x=(3/8)×(40-x)

=>(1/4)x =(120-3x)/8

=>8x =480-12x

=>8x+12x =480

=>20x =480

=>x =480/20

=>x =24

Therefore 1st part =24

2nd part =40-24=16