Question

Divide 40 into two parts such that 1/4th of one part is 3/8th of the other.​

Answer 1

Answer:

24 and 16

Step-by-step explanation:

Let the first part be x

Second part will be (40-x)

ATQ:

1/4(X) =3/8 (40-x)

On solving, we get :

X= 24

hence first part = 24

Second part = 16

Answer 2

Step-by-step explanation:

Question pt 1: Divide 40 into two parts

Here, we divide 40 into 2 parts. Let them be

x and 40-x.

Question pt 2: 1/4th of one part is 3/8th of the other.​

Here we add the equation-

Element 1= Since they say $\frac{1}{4}th$ part of one number, we can put

$\frac{1}{4}(40-x)$  

Element 2= Since they say $\frac{3}{8}th$ part of the other number, we can put

$\frac{3}{8}x$

Making the equation, we get

$\frac{1}{4}(40-x)$  =  $\frac{3}{8}x$

$\frac{40-x}{4}= \frac{3x}{8}\\8(40-x) = 4(3x)\\320-8x = 12x\\320 = 12x + 8x\\320 = 20x\\x = \frac{320}{20}\\\\x = 16$

Therefore, 2 numbers are

x = 16

40-x = 40-16 = 24