Question

Divide 40 into two parts such that 1/4th of one part is 3/8th of the other.

Answer 1

Answer:

The value of both pats is $24$ and $16$.

Step-by-step explanation:

Given: Divide $40$ into two parts.

To find: Both the parts.

Solution:

Let $40$ is decided into two parts $x$ and $y$.

$x+y=40$ ....... $(1)$

Two parts such that 1/4th of one part is 3/8th of the other.

$1/4x= 3/8y$

$x= 4$ × $3/8y$

$x=3/2y$ ........ $(2)$

Putting the value of equation$(2)$ in equation $(1)$.

$3/2y+y=40$

$5y=80$

$y=16$

Putting the value of $y=16$ in equation $(2)$.

$x=3/2$ × $16$

$x= 24$

Hence, both parts are $24,16$.