Divide 40 into two parts such that 1/4th of one part is 3/8th of the other. Find the answer with solution.
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let 40is decided into two part x and y
x + y = 40 •••••••(1)
1/4x = 3/8y
x = 4×3/8y
x = 3/2y •••••••••(2)
put the value of eq- 2 in eq- 1
3/2y+y = 40
5y = 80
y=16
x + y = 40 •••••••(1)
1/4x = 3/8y
x = 4×3/8y
x = 3/2y •••••••••(2)
put the value of eq- 2 in eq- 1
3/2y+y = 40
5y = 80
y=16
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