Question

Divide 40 into two parts such that 1/4th of one part is3/8th of the other

Answer 1

Let the first part of 40 be a. Since first part is a, other part should be 40 - a { sum of parts should be 40, a + ( 40 - a ) , a + 40 - a, a , therefore parts are a and 40 - a }.

It is given that 1 / 4 of one part is 3 / 8 of the other.

According to this question : -

= > 1 / 4 of one part = 3 / 8 of other

= > 1 / 4 of a = 3 / 8 of ( 40 - a )

= > 1 / 4 x a = 3 / 8 x ( 40 - a )

= > 8 / 3 x 1 / 4 x a = 40 - a

= > 2 / 3 x a = 40 - a

= > 2a = 3( 40 - a )

= > 2a = 120 - 3a

= > 3a + 2a = 120

= > 5a = 120

= > a = 24

Hence, parts are : -

• a = 24
• 40 - a = 40 - 24 = 16

Hence the required parts of 40 are 24 and 16. And, thus 40 = 24 + 16 { divided }.