Divide 4000 into 2 parts such that 15% of the first part equals 25% of the 2nd part? -
Answers
Answered by
39
Solution :-
Let the first part be 'x' and the second part be (4000 - x)
Now, according to the question.
15 % of the first part equals to the 25 % of the second part.
⇒ (x*15)/100 = [25*(4000 - x)]/100
⇒ 3x/20 = (4000 - x)/4
After cross multiplication, we get.
⇒ (3x*4) = 20*(4000 - x)
⇒ 12x = 80000 - 20x
⇒ 12x + 20x = 80000
⇒ 32x = 80000
⇒ x = 80000/32
⇒ x = 2500
Therefore, the other part = 4000 - 2500
= 1500
So, the first part is 2500 and the second part is 1500.
Answer.
Let the first part be 'x' and the second part be (4000 - x)
Now, according to the question.
15 % of the first part equals to the 25 % of the second part.
⇒ (x*15)/100 = [25*(4000 - x)]/100
⇒ 3x/20 = (4000 - x)/4
After cross multiplication, we get.
⇒ (3x*4) = 20*(4000 - x)
⇒ 12x = 80000 - 20x
⇒ 12x + 20x = 80000
⇒ 32x = 80000
⇒ x = 80000/32
⇒ x = 2500
Therefore, the other part = 4000 - 2500
= 1500
So, the first part is 2500 and the second part is 1500.
Answer.
Answered by
11
Answer:
Step-by-step explanation:
First part =x
Second part =4000-x
So,x+15/100=25×4000-x/100
3x/20=4000-x/4(crossmultiplication)
( 3x×4)=20(4000-x)
12x=80000-20x
12x+20x=80000
32x=80000
X=2500
Second part =4000-x
=1500
Hence firs first part will be e rupees 2500 and second part will be rupees 1500
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