Question

divide 420 into two parts such that 10% of first part is equal to 20% of 2nd part find value of first part

Answer 1

Hey,
Let the first part be X and the second part be y,So,ATQ,
10% of x+20% of y=420
10/100x+20/100y=420
1/10x+1/5y=420 (equation )
Now on solving u can get the answer friend ,
HOPE YOU HAVE GOT IT!!
HAVE A NICE DAY :-):-)

Answer 2

↑ Here is your answer ↓
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10% of first part is equal to 20% of second part,

Let first part and second part be 'x' and 'y' respectively,

$420 * 10/100*x = 420 * 20/100 * y$

$420x/10 = 420y/5$

Cancel 420,

$x/10 = y/5$

$5x = 10y$

$x = 2y$

Now substitute,

$x + y = 420$

$2y + y = 420$

$3y = 420$

$y = 420/3$

$y = 140$

$x = 140/2 = 70$