Question

divide 44(x^4-5x^3-24x^2) by 11x(x-8)

From the chapter factorisation

Answer 1

if u understand or not then plzz tell me in comment.

Answer 2

Final Answer:

The expression $44(x^4-5x^3-24x^2)$ is divided by another expression $11x(x-8)$, using the method of factorization, to yield the expression $4x(x+3)$.

Given:

The expressions $44(x^4-5x^3-24x^2)$ and $11x(x-8)$.

To Find:

The expression $44(x^4-5x^3-24x^2)$ is to be divided by another expression $11x(x-8)$, using the method of factorization.

Explanation:

Remember the following important points.

• Factorization of any number or expression results in the pertinent factors, by dint of which the referred number or expression gets simplified.

• The factors obtained from the method of factorization cancel each other, only when they are identical and non-zero.

Step 1 of 2

Simply the expression $44(x^4-5x^3-24x^2)$ using the method of factorization in the following way.

$44(x^4-5x^3-24x^2)\\=44x^2(x^2-5x-24)\\=44x^2(x^2-8x+3x-24)\\=44x^2[x(x-8)+3(x-8)]\\=44x^2(x-8)(x+3)$

Step 2 of 2

Divide the simplified form of the expression $44(x^4-5x^3-24x^2)$ by the expression $11x(x-8)$.

$=44x^2(x-8)(x+3)\div 11x(x-8)\\=\frac{44x^2(x+3)}{11x}\;\;\;\;[as\;x\ne 8]\\=4x(x+3)$

Therefore, the required expression that is obtained when the expression $44(x^4-5x^3-24x^2)$ is divided by another expression $11x(x-8)$, using the method of factorization, is $4x(x+3)$.

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