Question

divide - 45 x cube y cube Z cube by ? 9 X​

Answer 1

Did you just need an answer or to learn different method?

Answer 2

Question:

Divide $\frac{- 45x^3 y^3 z^3}{9x}$

Answer:

$\boxed{\bold{- 5x^2y^3z^3}}$

Step-by-step explanation:

→ $\frac{- 45x^3 y^3 z^3}{9x}$

→ $\frac{\cancel{-45x^3} y^3 z^3}{\cancel{9x}}$

→ $\frac{-45x^3}{9x} \frac{y^3}{9x} \frac{z^3}{9x}$

→ $\frac{\cancel{-45x^3}}{\cancel{9x}} \frac{y^3}{9x} \frac{z^3}{9x}$

→ $\frac{-5x^2}{1} \frac{y^3}{9x} \frac{z^3}{9x}$

→$\frac{-5x^2 y^3 z^3}{1}$

→$\boxed{\bold{\purple{- 5x^2y^3z^3}}}$

Here, we've to, just divide the numerator by the denominator to get our required answer.

Here, we can't divide y³ and z³ by 9x as the variable isn't same.

- 45x³ and 9x both are having the same variable so that we can also divide it simply.

Steps 3, 4 and 5 are not needed as they are just for your understanding.

In step 3: the denominator 9x is common for all the variables. So, I'd just segregated them. (Just for your understandings)

In step 4: I'd cancelled - 45x^3 and 9x as they both are havin' same variable.

$\boxed{\red{\bold{Remember:}}}$

- 45x³y³z³ is the same variable as they aren't segregated by any mathematical operations such as plus (+) or minus (-) sign.

Terms can't be segregated by multiplication and division sign.