divide ₹4864 into three parts such that the second part is five times the first and the ratio of the second part to the third part is 3:4
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Let parts be x, y, and z
As per question,
=> y = 5x ... (1)
=> y:z = 3/4
=> 5x:z = 3/4 (from 1)
=> z = 20x/3
x+y+z = 4864
=> x+5x+(20x/3) = 4864
=> (18x+20x)/3 = 4864
=> 38x/3 = 4864
=> x = 4864*3/38 = Rs. 384
=> y = 5(384) = Rs. 1920
=> z = 20(384)/3 = Rs. 2560
As per question,
=> y = 5x ... (1)
=> y:z = 3/4
=> 5x:z = 3/4 (from 1)
=> z = 20x/3
x+y+z = 4864
=> x+5x+(20x/3) = 4864
=> (18x+20x)/3 = 4864
=> 38x/3 = 4864
=> x = 4864*3/38 = Rs. 384
=> y = 5(384) = Rs. 1920
=> z = 20(384)/3 = Rs. 2560
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