Question

divide -4a^3 + 4a^2 + a ÷ 2a​

Answer 1

Step-by-step explanation:

$= > - 4 {a}^{3} + 4 {a}^{2} + a \div 2a$

After dividing we get :-

$\bold{ = - 2 {a}^{2} + 2a - 1} (quotient)$

$\bold{ = 3a}(remainder)$

Check:-

$\bold{\boxed{Dividend=Divisor ×Quotient +Remainder}}$

$\bold{\red{- 4 {a}^{3} + 4 {a}^{2} + a }}= 2a \times ( - 2 {a}^{2} + 2 a - 1) + 3a$

$= - 4 {a}^{3} + 4 {a}^{2} - 2a + 3a$

$\bold{\red{ = - 4 {a}^{3} + 4 {a}^{2} + a}}$

Proved ✓