Question

the initial velocity during lunch ing of the mangal yaan must be great than of the earth​

Answer 1

Explanation:

the initial velocity of mangalyaan should be escape velocity so that it could escape the earth.

Orbital velocity=

$v0 = \sqrt{g \: } r$

$escape \: velocity = \sqrt{2}vo = \sqrt{2g} r$

$therefore \: if \: the \: orbita \: velocity \: of \: satellite \: is \: increased \sqrt{2 \:} times \: the \: satellite \: willleave \: the \: earth.$