divide 4x^3-3x^2+2x+60 by x+2 find the quotient and remainder
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Solution:
⠀⠀⠀x+2) 4x³-3x²+2x+60 ) 4x²-11x+24
⠀⠀⠀⠀⠀⠀4x³+8x²
⠀⠀⠀⠀⠀⠀-⠀⠀-
⠀⠀⠀⠀⠀_____________
⠀⠀⠀⠀⠀⠀-11x²+2x
⠀⠀⠀⠀⠀⠀-11x²-22x
⠀⠀⠀⠀⠀⠀+⠀⠀+
⠀⠀⠀⠀⠀_____________
⠀⠀⠀⠀⠀⠀24x+60
⠀⠀⠀⠀⠀⠀24x+48
⠀⠀⠀⠀⠀-⠀⠀⠀-
⠀⠀⠀⠀⠀_____________
⠀⠀⠀⠀⠀⠀⠀⠀⠀12
Quotient=4x²-11x+24
Remainder=12
_______________________________
Verification:
Divided=Quotient×Divisor+Remainder
L.H.S.=4x³-3x²+2x+60
R.H.S.=(4x²-11x+24)(x+2)+12
⠀⠀⠀⠀=4x³-11x²+24x+8x²-22x+48+12
⠀⠀⠀⠀=4x³-3x²+2x+60
⠀⠀⠀⠀=L.H.S.
Hence, verified.
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