divide 534 into 3 parts such that the 2nd part will be 32 less than twice the first and the 3rd will be 18 more than the 1st
Answers
Answered by
32
let first part be x......then second part will be (2x-32).... and third part will be (x+18)
ATQ
x+(2x-32)+x+18=534
x+2x-32+x+18=534
on solving this x=137
first part=137
second part=242
third part=155
you can check it adding them , answer will be 534
hope it helped you
ATQ
x+(2x-32)+x+18=534
x+2x-32+x+18=534
on solving this x=137
first part=137
second part=242
third part=155
you can check it adding them , answer will be 534
hope it helped you
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Answered by
25
let 1st part be = x
then 2nd part = 2x-32
3rd part = x +18
2x+x-32+x+18=534
4x-14=534
4x=534+14
x=548
x=137
2x-32=242
x+18=155
then 2nd part = 2x-32
3rd part = x +18
2x+x-32+x+18=534
4x-14=534
4x=534+14
x=548
x=137
2x-32=242
x+18=155
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