Math, asked by Anushi007, 1 year ago

divide 54 into 3 parts in AP such that 5 times the smallest exceeds the largest by 6

Answers

Answered by CKS
15
hope it helps and have a good day

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Answered by throwdolbeau
16

Answer:

The required three equal parts are : 7, 18 and 29

Step-by-step explanation:

Let three equal parts are : a - d , a , a + d with common difference d

According to given condition,

a - d + a + a + d = 54

⇒ 3·a = 54

⇒ a = 18

Now, 5·(a - d) = a + d + 6

⇒ 5·a - 5·d = a + d + 6

⇒ 6·d = 4·a - 6

Putting value of a = 18 in the above equation

⇒ 6·d = 4 × 18 - 6

⇒ 6·d = 66

⇒ d = 11

Now, the assumed three equal parts are : a - d , a , a + d

                                                                    : 18 - 11, 18, 18 + 11

                                                                    : 7, 18, 29

Hence, the required three equal parts are : 7, 18 and 29

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