divide 54 into 3 parts in AP such that 5 times the smallest exceeds the largest by 6
Answers
Answered by
15
hope it helps and have a good day
.. .. .. .. .. .. .. .. .. .. .. ..
.. .. .. .. .. .. .. .. .. .. .. ..
Attachments:
Answered by
16
Answer:
The required three equal parts are : 7, 18 and 29
Step-by-step explanation:
Let three equal parts are : a - d , a , a + d with common difference d
According to given condition,
a - d + a + a + d = 54
⇒ 3·a = 54
⇒ a = 18
Now, 5·(a - d) = a + d + 6
⇒ 5·a - 5·d = a + d + 6
⇒ 6·d = 4·a - 6
Putting value of a = 18 in the above equation
⇒ 6·d = 4 × 18 - 6
⇒ 6·d = 66
⇒ d = 11
Now, the assumed three equal parts are : a - d , a , a + d
: 18 - 11, 18, 18 + 11
: 7, 18, 29
Hence, the required three equal parts are : 7, 18 and 29
Similar questions