divide 56 in four parts in ap such that the ratio of the product of their extremes (1st and 4th) to the product of means(2nd and 3rd)is 5:6
Answers
Answered by
8
Answer:
Take the terms as a-3d, a-d, a+d, a+3d
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Answered by
1
Answer:
6 , 12 , 16 , 20 ,
Step-by-step explanation:
ANSWER
Let the four parts be a−3d,a−d,a+d,a+3d
Sum, 4a=56
a=14
(a−d)(a+d)
(a−3d)(a+3d)
=
6
5
6(a
2
−9d
2
)=5(a
2
−d
2
)
a
2
=49d
2
d=±2
For d=2,
Numbers are 8,12,16,20.
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