Question

Divide 56 into 2 parts such that 3 times the first part exceeds one third of the second by 48. The parts are

Answer 1

Answer:The parts are 20 and 36.

Step-by-step explanation:

Let the 1st part be x.

Therefore,

second part= 56-x

3 times first part=3*x=3x

1/3rd of 2nd part=(56-x)/3

According to the question,

3x-(56-x)/3=48

= 9x-56+x=144

= 10x=144+56

= 10x=200 or, x=20

Therefore,

1st part=20

2nd part=(56-20)=36.