Question

Divide 56 into 2 parts such that three times the first part exceeds one third of the second part by 48

Answer 1

Let the first part be x
other part is 56 - x
three times the first part exceeds one third of the second party by 48
3x = 1/3(56-x) + 48
9x = 56-x + 144
9x + x = 200
10x = 200
x = 20
First part 20
Second part 36

Answer 2

first part 20
second part 36