Question

Divide 56 into four parts which r in AP such tht the ratio of product of extremes to the product of means is 5:6.

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Answer 1

Let the 4 parts be
a-3d , a-d , a+d , a+3d
Given ,
4a =56 or a = 14
Also,
(a-3d)(a+3d) / (a-d)(a+d) = 5/6
solve it we get ,

d = +- 2 ( plus minus 2)
Hence parts r
14-3×2 , 14-2 , 14+2 , 14+3×2
ie..
8 , 12 , 16 and 20....
Hope it will help U