Question

Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are

Answer 1

let one part be x

so,the other part is 56 - x

according to question

3x-(56-x/3)=48

(9x-56+x)/3=48

10x-56=144

10x=200

x=20

so one part is 20 and other part is 36