divide 56 into two parts such that three times the first part exceeds one third of the second by 48.the part are
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Let the two parts be x and 56-x
3x = 1/3(56-x)+48
9x = 56-x + 144
10x = 200
X = 20
So the two parts are 20 and 36
3x = 1/3(56-x)+48
9x = 56-x + 144
10x = 200
X = 20
So the two parts are 20 and 36
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