Question

divide 56 into two parts such that three times the first part exceeds one third of the second by 48: the parts are​

Answer 1

let one part be x. then other is 56-x.

3x-(1/3*(56-x))=48

9x/3-(56-x)/3=48

9x-56+x=48*3

10x= 144+56= 200

x=200/10=20

other part =56-x=56-20=36