Question

divide 581 among a,b,c so that 4a=5b=7c

Answer 1

here , we have to divide 581 in A,B,C such that 
A + B + C = 581 ...................................(i)
let 4A = 5B = 7C = x
=> A = x / 4
=> B = x / 5
=> C = x / 7
on placing values of A,B,C in eq(i)
we get
(x/4) + (x/5) + (x/7) = 581
=> x * ( (1/4) + (1/5) + (1/7) ) = 581
=> x * ( (35+28+20) / 140 ) = 581 .................LCM (4,5,7) = 140
=> x * (83 / 140) = 581
=> x = 581 * 140 / 83
=> x = 140 * 7 ......................................(ii)

now , from eq(ii)
we get 
A = x / 4 = 140 * 7 / 4 = 35 * 7 = 245
B = x / 5 = 140 * 7 / 5 = 28 * 7 = 196
C = x / 7 = 140 * 7 / 7 = 140

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Answer 2

Answer:

Let A = 100

Therefore 5B = 4A

5B = 4 * 100 = 400

          400

B = -----------  => B = 80

           5

Then 7C =  5B

7C = 400

C = 400 / 7

                                    400

A : B : C =  100 : 80 : --------

                                      7

                 700 : 560 : 400

A : B : C = -------------------------

                              7  

A : B : C = 700 : 560 : 400

A : B : C = 70 : 56 : 40

A : B : C = 35 : 28 : 20

A + B + C = 581

35 + 28 + 20 = 83

Therefore A =

83 = 581                    581 * 35

                 = >     A = --------------- =  245

35 = A                               83

83 = 581                     581 * 28

                = >       B = --------------- =  196

28 = B                               83

83 = 581                     581 * 20  

                = >       C =  ------------- =  140

20 = C                              83

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