Divide 64 into two parts in such a way that twice of one part exceeds 5 times of the other by 2
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Answer:
46 and 18
Step-by-step explanation:
Let the first part be x.
Second part = (64-x)
According to Question,
2x = 5(64-x)+2
=> 2x = 320-5x+2
=> 2x+5x = 320+2
=> 7x = 322
=> x = 322/7
=> x = 46
Hence, first part = 46
Second part = 64 - 46 = 18
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