Question

Divide 64 into two parts in such a way that twice of one part exceeds 5 times of the other by 2


Please help me.​

Answer 1

Answer:

46 and 18

Step-by-step explanation:

Let the first part be x.

Second part = (64-x)

According to Question,

2x = 5(64-x)+2

=> 2x = 320-5x+2

=> 2x+5x = 320+2

=> 7x = 322

=> x = 322/7

=> x = 46

Hence, first part = 46

Second part = 64 - 46 = 18