Question

Divide 68 into 2 parts so that the larger number exceeds the smaller one by 6.

Answer 1

Let the smaller no. be x

Then,larger no.=x+6

So, x+x+6=68

2x+6=68

2x=62

x=31

So smaller no.=31

larger no.=x+6=31+6=37

Answer 2

Answer:

31

Step-by-step explanation:

Let smaller number be x

larger number = x=6

x+x+6=68

2x+6=68

2x=68-6

2x=62

x= 62÷ 2

x= 31