Question

Divide 68 into two part such that the difference of 4/7 of one part and 2/5 of the other part is Zero.
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Answer 1

Answer:

hope its helpful dear...

Answer 2

Step-by-step explanation:

Answer:

34 is divided into two parts in such a way that

first part = 14

and

second part = 20

Explanation:

Given number = 34

Let 34 is divided into two parts

i.e

First part = x

Second part = (34-x)

According to the problem given,

\begin{gathered}\frac{4}{7}\:of \: first \: part\\=\frac{2}{5} \: of\: second \: part \end{gathered}74offirstpart=52ofsecondpart

\implies \frac{4}{7}\times x = \frac{2}{5} \times (34-x)⟹74×x=52×(34−x)

Do the cross multiplication, we get

\implies 20x = 14(34-x)⟹20x=14(34−x)

\implies 10x = 7(34-x)⟹10x=7(34−x)

\implies 10x=7\times 34 -7x⟹10x=7×34−7x

\implies 10x+7x = 7\times 34⟹10x+7x=7×34

\implies 17x = 7\times34⟹17x=7×34

\implies x = \frac{7\times 34}{17}⟹x=177×34

After cancellation,we get

\implies x = 14⟹x=14

First part = x = 14

Second part = 34-x

= 34 - 14

= 20

Therefore,

34 is divided into two parts in such a way that

first part = 14

and

second part = 20

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