Divide 690 into 3 parts in the ratio 2:3:5.
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Let the number be 2x,3x and 5x
A/C:-
☞2x+3x+5x=690
=>10x=690
=>x=690/10
=>x=69
Now, 2x=2×69=138
3x=207
5x=345
Answered by
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Step-by-step explanation:
To divide a number into three parts in a given ratio
Let the number be p. It is to be divided into three parts in the ratio a : b : c.
Let the parts be x, y and z. Then, x + y + z = p .................... (i)
and x = ak, y =bk, z = ck.................... (ii)
Substituting in (i), ak + bk + ck = p
⟹ k(a + b + c) = p
Therefore, k = pa+b+cpa+b+c
Therefore, x = ak = apa+b+capa+b+c, y = bk = bpa+b+cbpa+b+c, z = ck = cpa+b+ccpa+b+c.
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