divide (6x^3-26x-21+x^2) by (-7+3x)
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Hii friend,
P(X) => 6X³-26X-21+X²=> 6X³+X²-26X-21
G(X) => -7+3X => 3X-7
On dividing P(X) by G(X) we get,
Remainder => 0
Quotient => 2X²+5X+3
REMAINDER CAME ZERO IT MEANS 3X-7 IS A FACTOR OF THE GIVEN POLYNOMIAL.
THEREFORE,
2X²+5X+3
=> 2X²+6X-X+3
=> 2X(X+3) -1(X+3)
=> (X+3) (2X-1)
=> (X+3) = 0 OR (2X-1) = 0
=> X = -3 OR X = 1/2
Hence,
-3 , 1/2 and 7/3 are the zeros of the given polynomial.
HOPE IT WILL HELP YOU..... :-)
P(X) => 6X³-26X-21+X²=> 6X³+X²-26X-21
G(X) => -7+3X => 3X-7
On dividing P(X) by G(X) we get,
Remainder => 0
Quotient => 2X²+5X+3
REMAINDER CAME ZERO IT MEANS 3X-7 IS A FACTOR OF THE GIVEN POLYNOMIAL.
THEREFORE,
2X²+5X+3
=> 2X²+6X-X+3
=> 2X(X+3) -1(X+3)
=> (X+3) (2X-1)
=> (X+3) = 0 OR (2X-1) = 0
=> X = -3 OR X = 1/2
Hence,
-3 , 1/2 and 7/3 are the zeros of the given polynomial.
HOPE IT WILL HELP YOU..... :-)
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