Question

Divide 72 into two parts so that the larger part exceeds the smaller by 12. Find both the parts. (Please answer the question as fast as possible. Whoever answers the question first, I will him or her Brainlist)

Answer 1

Given : Divide 72 into two parts so that bigger number exceeds the smaller by 12 .

To Find : Find the two numbers

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SolutioN : As we have to divide the no. in two parts so first let us form the Equation and solve it . Let's Solve :

$\maltese$ According to the Question :

$\longmapsto$ Let the Smaller no. be y .So,

$\qquad \; {\pmb{\sf{ Smaller \; Number = y }}}$

$\longmapsto$ Bigger no. exceeds the smaller one by 12 .So,

$\qquad \; {\pmb{\sf{ Bigger \; Number = y + 12 }}}$

$\maltese$ Calculating the Value of y :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \bigg\{ Bigger \; No. \bigg\} + \bigg\{ Smaller \; No. \bigg\} = 72 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \bigg( y + 12 \bigg) + y = 72 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 2y + 12 = 72 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 2y = 72 - 12 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 2y = 60 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { y = \dfrac{60}{2} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { y = \cancel\dfrac{60}{2} } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf{ y = 30 }}}}} \; {\orange{\bigstar}} \\ \\ \\ \end{gathered}$

$\maltese$ Calculating the Numbers :

• Smaller No. = y = 30
• Bigger No. = y + 12 = 30 + 12 = 42

$\therefore \;$ The two Numbers are 30 and 42 .

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Answer 2

refer the given attachment