divide 750 into three parts such that the second number is five- sixths the first and third number is four-fifths the second
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let first no be x
let second no be y
then third no must be 750-(x+y)
b. t. p. y=(5*x) /6
then 750-(x+y) =4/5 th of y
substituting value of y by 5*x/6
now this forms an equation
750-{x+(5*x/6)}=2x/3
solve this and get the value of x as 300
now y=5x/6
value of y is 250
then final no is 750-300-250
200
let second no be y
then third no must be 750-(x+y)
b. t. p. y=(5*x) /6
then 750-(x+y) =4/5 th of y
substituting value of y by 5*x/6
now this forms an equation
750-{x+(5*x/6)}=2x/3
solve this and get the value of x as 300
now y=5x/6
value of y is 250
then final no is 750-300-250
200
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