Question

DIVIDE 750 INTO TWO PARTS SO THAT 10% OF ONE PART EQUALS 20% OF THE OTHER PART.

Answer 1

total = 750

part 1 = x

part 2 = 750 - x          [ i.e., if u take the 1st part "x" from the total, u get the 2nd part]

10 % of x= 20 % (750 - x)

10/100 * x = 20/100 (750 - x)

10/100 *x= 15000/100-20/100 x

10/100x+20/100x= 15000/100  [x terms on one side...constants on the other side]

30/100 x  =150   [cancelling 0 in 15000/100]

3/10 x = 150       [cancelling 0 in 30/100]

x = 150 * 10/3

x= 50 * 10

x= 500

part 1 = x

          = 500

part 2 = 750 - x

         = 750 - 500

          = 250

[pls check the answer)

Answer 2

Answer:

1st Part = 750

2nd Part = 250

Step-by-step explanation:

Let The $1^{st}$ Part be (x)

             $2^{nd}$ Part be (750 - x)

⇒ 10% × (x) = 20% × (750 - x)

⇒ $\frac{10}{100}x = \frac{20}{100}(750 - x)$

⇒ $\frac{30}{100}x = 150$

⇒ $x = 50 X100$

⇒ $x = 500$

Therefore,

$\left \{{1st Part = 500} \atop {2nd Part = 250}} \right.$