Math, asked by elizathapa1, 1 year ago

divide (8+19x+x2-6x3) by (2-3x2+5x) and verified the division algorithm

Answers

Answered by siddhartharao77
12

                                2x   +   3
                               -----------------------------------------
- 3x^2  +  5x  + 2)  -6x^3  +  x^2   +   19x   +   8 

                              -6x^3   + 10x^2  +  4x

                             ----------------------------------------------

                                              -9x^2  +  15x  +   8

                                              - 9x^2  +  15x  +  6

                            ---------------------------------------------------

                                                                        2.



Now,

Quotient = 2x + 3, Remainder = 2, Dividend = -6x^3 + x^2 + 19x + 8, Divisor = -3x^2 + 5x + 2.


Divisor * Quotient +  Remainder.

(-3x^2 + 5x + 2) * (2x + 3) + 2

-6x^3 + x^2 + 19x + 6 + 2

-6x^3 + x^2 + 19x + 8.


Hence Verified.


Hope this helps!

abhi569: nice bro
siddhartharao77: Thanks Bhai.
Anonymous: WOW BHAI !
Answered by Anonymous
10
Hi,

Please see the attached file!


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