Divide 8 into two parts such that the sum of the reciprocals is 2 by 3
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Let the two parts be x & y
Then... x+y =8 (1)
1÷x + 1÷y = 2÷3 (2)
Solving (2) we get 3x + 3y = 2xy
From (1) y= 8- x (3)
Substitute (3) in (2)
3x + 3 (8-x) == 2x (8-x)
>> x = 6 or 2 ( if X = 2 ; y = 6 & vise versa )
Then... x+y =8 (1)
1÷x + 1÷y = 2÷3 (2)
Solving (2) we get 3x + 3y = 2xy
From (1) y= 8- x (3)
Substitute (3) in (2)
3x + 3 (8-x) == 2x (8-x)
>> x = 6 or 2 ( if X = 2 ; y = 6 & vise versa )
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