divide 8 into two parts such that the sum of their square is 34
Answers
Answered by
1
3 and 5
3×3 =9
5×5=25
9+25=34
3×3 =9
5×5=25
9+25=34
Answered by
2
Let one part be = x
Then other part is = 8-x
A.T.Q,
(x^2) + (8-x)^2 = 3
x^2 + ( 64 + x^2 -16x ) = 34
2x^2 - 16x = 34 - 64
2x^2 - 16x = -30
2x^2 - 16x + 30 =0
2 ( x^2 - 8x +15 ) =0
x^2 - 8x + 15 =0 /2
x^2 - 5x - 3x + 15 =0 ( 0/2 =0 )
x ( x - 5 ) - 3 ( x - 5 ) =0
( x - 3 ) ( x - 5 ) = 0
therefore , X = 3 , 5
1 part = 3 , 5
2 part = 5 , 3
Please mark iy as brainliest answer if helpful ......
Then other part is = 8-x
A.T.Q,
(x^2) + (8-x)^2 = 3
x^2 + ( 64 + x^2 -16x ) = 34
2x^2 - 16x = 34 - 64
2x^2 - 16x = -30
2x^2 - 16x + 30 =0
2 ( x^2 - 8x +15 ) =0
x^2 - 8x + 15 =0 /2
x^2 - 5x - 3x + 15 =0 ( 0/2 =0 )
x ( x - 5 ) - 3 ( x - 5 ) =0
( x - 3 ) ( x - 5 ) = 0
therefore , X = 3 , 5
1 part = 3 , 5
2 part = 5 , 3
Please mark iy as brainliest answer if helpful ......
Similar questions