Question

divide 84 CHOCOLATES BETWEEN TOW CHILDREN in the ratio 7:5

Answer 1

7x + 5x = 84
12x =84
x=84/12
x=7
7x= 7X7 = 49
5x= 5X7 = 35
Hence on student gets 49 chocolates and other gets 35

Answer 2

Question ☆ -:

Divide 84 chocolates between 2 children in the ratio 7 : 5.

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Answer ☆ -:

Number of chocolates = 84.

Number of children = 2.

Ratio = 7 : 5.

Sum of the terms = 7 + 5 = 12.

So,

Share of the 1st child = $\frac{7}{12} \times 84 = 49 \: chocolates.$

Share of the 2nd child = $\frac{5}{12} \times 84 = 35 \: chocolates.$

Thus, the 1st child got 49 chocolates and the 2nd child got 35 chocolates.

Verification ☆ -:

Just add up these numbers and see if you get 84.

$49 + 35 = 84$

Since 49 + 35 = 84,

Hence verified.

Hope it helps! :)