Math, asked by prernashankar11, 5 months ago

. Divide: (8a²b³c + 4a²b²c² - 6a²bc) ÷ ( 2a²bc)​

Answers

Answered by Anonymous
1

Answer:

4b^2+2bc-3

Step-by-step explanation:

take 2a^2bc common from given we get

2a^2bc(4b^2+2bc-3)÷2a^2bc

= (4b^2+2bc-3)

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