divide 90 into two parts so that ratio between their difference and sum is 1:90
Answers
Answered by
33
Answer. 40 and 50.
Solution
Let x be the smaller of the two parts.
Then the other part is 90-x.
Notice that the sum of these parts is precisely 90, while the difference is (90-x) - x = 90-2x.
Then, according to the condition,
90-2x/90 = 1/9
90-2x=90/9
90 - 2x = 10,
2x = 90 - 10 = 80,
x = 80/2 = 40.
Thus the smallest part is 40, and the other part is 90-40 = 50.
Solution
Let x be the smaller of the two parts.
Then the other part is 90-x.
Notice that the sum of these parts is precisely 90, while the difference is (90-x) - x = 90-2x.
Then, according to the condition,
90-2x/90 = 1/9
90-2x=90/9
90 - 2x = 10,
2x = 90 - 10 = 80,
x = 80/2 = 40.
Thus the smallest part is 40, and the other part is 90-40 = 50.
Answered by
4
Answer:
45.5 and 44.5
Step-by-step explanation:
Let 2 parts be x and 90-x
x-90-x:x+90-x::1:90
2x-90/90=1/90
2x-90=1
2x=91
x=45.5
One number is 45.5
Other number is 90-45.5=44.5
Therefore, two numbers are 45.5 and 44.5
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