Math, asked by mdaltafraza75, 1 year ago

divide 90 into two parts so that the ratio between their difference and sum is 1 is to 9​

Answers

Answered by jacobpankavil
30

Answer:

40 and 50

Step-by-step explanation:

Let  x  be the smaller of the two parts. 

Then the other part is  90-x. 

Notice that the sum of these parts is precisely  90,  while the difference is  (90-x) - x = 90-2x. 

Then,  according to the condition, 

90-2x/90 = 1/9

90-2x=90/9

90 - 2x = 10

2x = 90 - 10 = 80

x = 80/2 = 40

Thus the smallest part is 40, and the other part is  90-40 = 50

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Answered by ishetabhatt
15

Answer: 40 and 50

Step-by-step explanation:

Let one part be x. The other is 90-x.

Given,

(90-x-x)/90 = 1/9

90-2x = 10

2x = 80

x = 40

Therefore the other part is 50.

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