Math, asked by sayemasuzana12345, 11 months ago

Divide 940 among A,B,C in the ratio 1/3,1/4,1/5.[tex][/tex]

Answers

Answered by palak1610
35

Step-by-step explanation:

let the parts to be distributed be :

x/3 , x/4 , x/5

acc. to question

x/3 + x/4 + x/5 = 940

20x + 15x + 12x / 60 = 940

20x + 15x + 12x = 940 × 60

47x = 940 × 60

x = 940 × 60/47

x. = 1200

therefore

x/3 = 1200/3

= 400

x/4 = 1200/4

= 300

x/5 = 1200/5

= 240

Answered by me175
5

Answer:

A will get $400

B will get $300

C will get $240

Step-by-step explanation:

Let the numbers be 1/3x, 1/4x, and 1/5x.

1/3x + 1/4x + 1/5x = 940

Now, find the common number that is divisible by 3, 4, and 5.

We can find that 60 is divisible. Multiply the denomenators to get 60. And then multiply the numerator with the number multiplied by the denominator. And we get 20/60x + 15/60x + 12/60x

20/60x + 15/60x + 12/60x = 940.

Add the numerators and we get 47/60x

47/60x = 940

47x = 940*60 = 56400

x = 56400/12 = 1200

Therefore,

1/3 * 1200 = 400

1/4 * 1200 = 300

1/5 * 1200 = 240.

Hope it helps!

Please mark this as the brainliest answer if you find it helpful!!!

Similar questions