Divide 940 among A,B,C in the ratio 1/3,1/4,1/5.[tex][/tex]
Answers
Step-by-step explanation:
let the parts to be distributed be :
x/3 , x/4 , x/5
acc. to question
x/3 + x/4 + x/5 = 940
20x + 15x + 12x / 60 = 940
20x + 15x + 12x = 940 × 60
47x = 940 × 60
x = 940 × 60/47
x. = 1200
therefore
x/3 = 1200/3
= 400
x/4 = 1200/4
= 300
x/5 = 1200/5
= 240
Answer:
A will get $400
B will get $300
C will get $240
Step-by-step explanation:
Let the numbers be 1/3x, 1/4x, and 1/5x.
1/3x + 1/4x + 1/5x = 940
Now, find the common number that is divisible by 3, 4, and 5.
We can find that 60 is divisible. Multiply the denomenators to get 60. And then multiply the numerator with the number multiplied by the denominator. And we get 20/60x + 15/60x + 12/60x
20/60x + 15/60x + 12/60x = 940.
Add the numerators and we get 47/60x
47/60x = 940
47x = 940*60 = 56400
x = 56400/12 = 1200
Therefore,
1/3 * 1200 = 400
1/4 * 1200 = 300
1/5 * 1200 = 240.
Hope it helps!
Please mark this as the brainliest answer if you find it helpful!!!