Question

the value of g at height equal to the radius of the earth from its surface is?​

Answer 1

Explanation:

g at a height h above the ground =>

$\frac{g}{ {(1 + \frac{h}{r} )}^{2} }$

where r is the radius of the earth so the value of g at height r from its surface is

$\frac{g}{{(1 + 1)}^{2} } = > \frac{g}{4}$

Hope it helps you.