Question

divide : 96 abc (3a-12)(5b-30)÷16(a-4)(b-6)​

Answer 1

Answer:

$\frac{96 abc (3a-12)(5b-30)}{16(a-4)(b-6)} \\ = \frac{96 abc \times 3(a-4) \times 5(b-6)}{16(a-4)(b-6)} \\ = \frac{96 abc \times 3 \times 5}{16} \\ = 90abc$