Question

Divide 99 into three parts which are in A.P. and are such that product of first two parts is 1023, then find the product of 1st and the 3rd number.
A) 1035
B) 1023
C) 1085
D) 1103

Answer 1

Let the three parts of 99 in A.P be (a - d) , a , (a + d) where, a > d

Now, clearly, (a + d) > a > (a - d)

Now, A to Q,

(a - d) + a + (a + d) = 207

=> 3a = 99

=> a = 33 --- (i) and,

(a - d) x a = 1023

=> 33 (33 - d) = 1023

=> d = (4761 - 4623)/33 = 2

Hence, a = 33 and d = 2

so, (a - d) = 67, a = 69 and (a + d) = 71

Hence, the three requred parts are, 67, 69 and 71 Ans..!!

Hope this helps you ☺️☺️❤️❤️

Answer 2

So our required answer is 1085 i. e option C