Math, asked by mhemangi2870, 1 year ago

The father age is 3 years more than three times a son age 3 year hence the age of father will be 10 year more twice the son age find their present age

Answers

Answered by harshita27123
3
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Answered by Anonymous
16

Solution:-

Let the Age of Son be "x" years.

=> Fathers Age = ( 3x + 3) years.

3 Years Hence,

Age of Son = (x+3) yrs.

& Age of Father = (3x + 6) yrs.

A.T.Q.

=> 3x + 6 = 2 ( x + 3 ) + 10

=> 3x + 6 = 2x + 6 + 10

=> x = 10 years.

Hence,

Age of Father = 3x + 3 = 33 yrs.

& Age of Son = x = 10 yrs.


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