Question

divide :-
(9a^2+24ab+16b^2)by(3a+4b) ​

Answer 1

$\bf\red{Answer-}$

$\frac{9 {a}^{2} + 24ab + 16 {b}^{2} }{3a + 4b} = \frac{(3a + 4 {b})^{2} }{3a + 4b} = \frac{(3a + 4b)(3a - 4b)}{3a + 4b} = 3a - 4b \: is \: the \: answer$