Question

divide a linesegment of length 14cm internally in the ratio 2:5​

Answer 1

we should multiply with x for 2 and 5 in ratio 2:5

Answer 2

CONSTRUCTION

Step-by-step explanation:

• draw a line segment of 14 cm which is line segment AB.
• draw a ray which makes an acute angle $\angle BAX = 60^\circ$ with line segment.
• draw a ray which is parallel to AX and makes an acute angle $\angle ABY = \angle BAX$
• we will mark two points $A_1,A_2$  on ray AX  and  points $B_1,B_2,B_3,B_4,B_5$  on the ray in such a way that $AA_1=A_1A_2=BB_1=B_1B_2=B_2B_3=B_3B_4=B_4B_5$
• we will join $A_2B_5$ and this line will intersect  ray AB at a point P.
• thus, P is the point which divides AB  internally in the ratio of 2:5

#Learn more:

A point divides of length 14cm in the ratio 3:4, then the length of AX

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