Question

Divide a rope of length ##560\ cm## into ##2## parts such that twice the length of the smaller part is equal to ##\frac{1}{3}## of the larger part. Then find the length of the larger part is

Answer 1

Answer:

$\boxed{\underline{\Huge{\texttt{480 cm}}}}$

Step-by-step explanation:

Let the Smaller part be x

Then the Second part (Larger part) = 560 - x

Now, According To the Question :-

$2x = \dfrac{1}{3}(560- x)\\\\\implies 2x = \dfrac{560}{3} - \dfrac{x}{3}\\\\\implies 6x = 560 - x\\\implies 6x + x = 560\\\implies 7x = 560\\\implies x = 80$

So, smaller part = 80 cm

Larger part = (560 - 80) = 480 cm